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1 year in secs per Google is no 60*60*24*365
1 point by julien top top Sept 1, 2010 | hide | previous | favorite | 3comments
606024*365 = 31 536 000 yet Google states that it"s in reality : 31 556 926 seconds.http://www.google.com/search?q=1+year+in+secondsAnd Wolfram Alpha ring up : http://www.wolframalpha.com/input/?i=1+year+in+SecondsLeap years FTW!

likewise note that 1 month in job is 30.4368499.There just isn"t a an excellent way come convert between labels for details periods the time and units for measuring the passing of time. The trouble is that language and common consumption don"t make lot of a difference between the two. If girlfriend ask world how lengthy a day is, they"ll tell girlfriend 24 hours. Also Google will tell you that, but it isn"t true. A job is usually 24 hours. DST and leap seconds deserve to both change the size of a job though. For this reason a work isn"t a unit because that measuring time in ~ all. It"s a surname for a certain period of time. Leap secs can also mess v terms the seem bulletproof like "hour" or "minute". Once there"s a leap second, one minute the the year i do not care 61 seconds, and the matching hour becomes 3601 seconds.The just unit of time you deserve to reliably occupational with is the 2nd (and metric derivations thereof, favor millisecond).

distinction is actually 20,926. Leap years account for 21,600. Over there is quiet 326 secs to find.I yes, really wonder just how google counts them.



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It"s be cause a year is around 365.24 days. That method every 4 years we add a day, yet that in reality overcompensates, for this reason every century or so we skip a leap year:Years that space evenly divisible by 100 room not leap years, uneven they are additionally evenly divisible by 400, in which case they space leap years.<1><2> because that example, 1600 and also 2000 to be leap years, but 1700, 1800 and 1900 to be not. Similarly, 2100, 2200, 2300, 2500, 2600, 2700, 2900 and 3000 will not it is in leap years, however 2400 and 2800 will be.http://en.wikipedia.org/wiki/Leap_year