I to be not certain why nobody answered your question and also it more than likely won"t aid now. Buuuut, i went ahead and solved it:

Use 2 kinematic equations: vf = v0 + in ~ & vf2 = v0 + 2aΔx

1st find the final velocity using the 2nd eqn. And, then plug that right into the an initial equation and also solve for time.

You are watching: A car initially traveling at 15 meters per second north

a = 4.5m/s2

initial velocity= 15m/s

Δx = 45m

vf2 = v0 + 2aΔx = 152 +2(4.5)(45) = 630=

vf = √630 ≅25.1 m/s

Manipulating our first equation we get: (vf - v0)/a = t

t = (25.1 - 15)/4.5 = 2.24 s


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