**A regulation table tennis ball has a massive of 2.7g and is 40mm in diameter. What is its moment of inertia around an axis that passes v its center?**

**Concepts and reason**The concepts required to deal with this trouble are moment of inertia the the hollow sphere and conversion that units.First settle for the radius of the round from diameter and also convert mass to kilogram. Then, substitute the worths in the expression of moment of inertia of hollow ball to calculate the moment of inertia that the tennis ball about an axis the passes v its center.

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**Fundamentals**The radius the a ball is half of the diameter. The is,Here, **r** is the radius and also **d** is the diameter.The moment of inertia of hole sphere about an axis the passes through its center is,Here, ** I** is the minute of inertia,

**m**is the mass, and also

**r**is the radius.The relations used to coverts units room as follows:

**Answer:**

The relationship of diameter and radius is.

**Explanation:**The radius is half of the diameter the the tennis ball.

The expression of minute of inertia the the tennis sphere is,Substitute

because that**m**, and also in the equation and calculate the minute of inertia of the tennis ball about an axis that passes through its center.

The minute of inertia that the tennis ball around an axis that passes through its facility is

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**Explanation:**The tennis ball is make of a plastic cover through hollow inside. The hollow ball is the the next symmetry of the tennis ball.