21 x³ + 35 x² + 9 x + 15 = = 7 x² ( 3 x + 5 ) + 3 ( 3 x + 5 ) == ( 3 x + 5 ) ( 7 x² + 3 )That`s all. Thank you.

You are watching: Factor completely 21x3 + 35x2 + 9x + 15.

(7x^2+3)( 3x+5)

Step-by-step explanation:

21x^3 + 35x^2 + 9x + 15.

We will do factor by grouping

Rearranging the terms so I have the terms with a factor of 3 first and 5 last

Factor a 3x from the first two terms and 5 from the last two terms

21x^3 + 9x + 35x^2+ 15

3x(7x^2 +3) +5(7x^2+3)

Now factor out a (7x^2+3)

(7x^2+3)( 3x+5)

Step-by-step explanation: We are given to factorise some quadratic expressions.

We will be using the following factorisation formula: The factorisation is as follows:

We have Thus, option (B) is correct. Thus, option (B) is correct. Thus, option (B) is correct Thus, option (D) is correct. Thus, option (C) is the correct option. Thus, option (B) is the correct option. Thus, option (D) is correct.

The correct options are :

(4). (A) (5). (C) (6). (D) (7). (C) Step-by-step explanation: We are given to completely factor the following expressions :

Expression 4 :

The given expression is The factorization of expression (i) is as follows : So, option (A) is CORRECT.

Expression 5 :

The given expression is The factorization of expression (ii) is as follows : So, option (C) is CORRECT.

Expression 6 :

The given expression is The factorization of expression (iii) is as follows : So, option (D) is CORRECT.

Expression 7 :

The given expression is The factorization of expression (iv) is as follows : So, option (C) is CORRECT.

Cubic = (3x + 5)(7x^2 + 3)

Step-by-step explanation:

If you make up two groups of 2, you might be able to factor this using the distributive property. Let"s try it.

First group: 21x^3 + 35x^2 Take out 7x^2 as a common fact

First group: 7x^2(3x + 5)

Second group: 9x + 15 The HCF is 3

Second group: 3(3x + 5)

Now put your factors together in one long string.

Cubic = group 1 + group 2

Cubic = 7x^2 (3x + 5) + 3(3x + 5)

Note: If you had something like 7x^2 * y + 3 *y then you should see that the factors are y* (7x^2 + 3). So to solve the cubic, you should observe that (3x + 5) is a common factor.

Let y = 3x + 5

y(7x^2 + 3) Now substitute back for the y.

Cubic = (3x + 5)(7x^2 + 3)

is so easy: (3x + 5)(7x² + 3)

Step-by-step explanation:

1. 7x² × (3x + 5) + 9x + 15

2. 7x² × (3x + 5) + 3(3x + 5)

3. (3x + 5) × (7x² + 3)

the answer is D (3x + 5)(7x^2 + 3)

Step-by-step explanation:

I just took the exam and this was the correct answer for flvs

The complete factored form of given polynomial is

Step-by-step explanation:

Given polynomial

We have to factorize the given polynomial completely.

Consider the given polynomial

We will solve it by grouping of terms,

Grouping is collecting terms having some factors common

Taking common from first two term and 3 from last two state , we have, Now taking (3x +5) common from both terms , we have, Thus, the complete factored form of given polynomial is

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