If you know exactly how to solve word troubles involving the sum of consecutive also integers, friend should be able to easily solve word troubles that indicate the sum of consecutive odd integers. The key is to have actually a an excellent grasp that what odd integers are and how continually odd integers have the right to be represented.

Odd Integers

If you recall, an even integer is constantly 2 time a number. Thus, the general type of an even number is n=2k, wherein k is an integer.

So what does it mean when us say the an integer is odd? Well, it means that it’s one less or one much more than an even number. In various other words, weird integers room one unit much less or one unit more of an also number.

Therefore, the general form of one odd integer have the right to be expressed as n is n=2k-1 or n=2k+1, where k is one integer.


Observe the if you’re provided an also integer, that also integer is constantly in in between two weird integers. Because that instance, the also integer 4 is between 3 and also 5.

To illustrate this simple fact, take it a look at the diagram below.

You are watching: Sum of 3 consecutive odd integers


As you can see, no issue what even integer we have, it will always be in between two weird integers. This diagram likewise illustrates that an odd integer have the right to be stood for with either n=2k-1 or n=2k+1, wherein k is one integer.

Consecutive strange Integers

Consecutive strange integers space odd integers the follow each other in sequence. Girlfriend may uncover it tough to believe, but just like even integers, a pair of any type of consecutive odd integers are additionally 2 devices apart. Just put, if you select any odd integer native a collection of consecutive odd integers, then subtract the by the previous one, their difference will be +2 or simply 2.

Here are some examples:



When solving word problems, it yes, really doesn’t matter which general creates of an odd integer girlfriend use. Whether you use 2k-1 or 2k+1, the last solution will certainly be the same.

To prove it to you, we will deal with the very first word problem in 2 ways. Then because that the remainder of words problems, we will either usage the form 2k-1 or 2k+1.

examples of resolving the amount of consecutive Odd Integers

Example 1: discover the three consecutive odd integers whose amount is 45.


We will deal with this word difficulty using 2k+1 which is just one of the general develops of one odd integer.

Let 2k+1 it is in the first strange integer. Due to the fact that odd integers are additionally 2 units apart, the 2nd consecutive odd integer will be 2 an ext than the first. Therefore, \left( 2k + 1 \right) + \left( 2 \right) = 2k + 3 wherein 2k + 3 is the second consecutive odd integer. The third strange integer will certainly then it is in \left( 2k + 3 \right) + \left( 2 \right) = 2k + 5.

The sum of our three consecutive weird integers is 45, so our equation setup will be:


Now the we have our equation, let’s proceed and also solve because that k.

At this point, we have actually the value for k. However, note that k is no the first odd integer. If you evaluation the equation above, the first consecutive odd creature is 2k+1. For this reason instead, we will usage the value of k in stimulate to find the an initial consecutive weird integer. Therefore,

We’ll use the worth of k again to determine what the second and third odd integers are.

Second weird integer:

Third weird integer:

Finally, let’s inspect if the amount of the three consecutive weird integers is certainly 45.

Final price (Method 1): The 3 consecutive odd integers are 13, 15, and also 17, which once added, outcomes to 45.


This time, we will resolve the word trouble using 2k-1 which is additionally one of the general forms of an odd integer.

Let 2k-1 it is in the first continuous odd integer. As questioned in technique 1, odd integers are additionally 2 systems apart. Thus, we can represent our second continually odd integer as \left( 2k - 1 \right) + \left( 2 \right) = 2k + 1 and also the third consecutive odd integer together \left( 2k + 1 \right) + \left( 2 \right) = 2k + 3.

1st odd integer: 2k-1 2nd odd integer: 2k+13rd strange integer: 2k+3

Now that us know how to represent each continually odd integer, we simply need to translate “three continually odd integers whose sum is 45” into an equation.

Proceed and solve for k.

Let’s now use the value of k which is k=7, to recognize the 3 consecutive integers

First strange integer:
Second strange integer:
Third weird integer:

The last step for us to do is to verify the the amount of 13, 15, and 17 is in fact, 45.

Final prize (Method 2): The 3 consecutive odd integers whose amount is 45 room 13, 15, and also 17.

PROBLEM WRAP-UP: so what have actually we learned while addressing this difficulty using 2k-1 and also 2k+1? Well, come start, us were maybe to watch that whether we used 2k-1 or 2k+1, we still gained the same three consecutive strange integers 13, 15, and 17 whose amount is 45, thus satisying the given facts in our initial problem. So, it is clear that it doesn’t issue what general form of odd integers we use. Whether it’s 2k-1 or 2k+1, we will certainly still arrive at the same last solution or answer.

Example 2: The sum of four consecutive weird integers is 160. Uncover the integers.

Before we start solving this problem, let’s identify the necessary facts the are provided to us.

What execute we know?

The integers space odd and are consecutiveThe amount of the continually integers is 160 which also implies the we need to add the integersThe integers differ by 2 unitsEach integer is 2 more than the previous integer

With these facts in mind, we have the right to now represent our four consecutive weird integers. However although we can use one of two people of the two general creates of strange integers, i.e. 2k-1 or 2k+1, we’ll just use 2k+1 to represent our first odd continually integer in this problem.

Let 2k+1, 2k+3, 2k+5 , and 2k+7 it is in the 4 consecutive odd integers.

Proceed by creating the equation then deal with for k.

Alright, for this reason we gained k=18. Is this our an initial odd integer? The prize is, no. Again, remember that k is no the very first odd integer. Yet instead, we’ll use its value to discover what ours consecutive weird integers are.

What’s left for united state to do is to inspect if 160 is undoubtedly the amount of the consecutive odd integers 37, 39, 41, and also 43.

Example 3: uncover the three consecutive odd integers whose amount is -321.

Important Facts:

We require to add three integers that are consecutiveSince the integers are odd, they room 2 systems apartThe amount of the 3 consecutive strange integers should be -321 The sequence of strange integers will much more likely involve negative integers

Represent the three consecutive weird integers. For this problem, we will usage the general kind 2k-1 to represent our first consecutive weird integer. And since strange integers are 2 systems apart, climate we have 2k+1 together our second, and 2k+3 as our third consecutive integer.

Next, interpret “three continuous odd integers whose sum is -321” into an equation and also solve for k.

See more: Zn+Hcl=Zncl2+H2 - How To Balance: Zn + Hcl = Zncl2 + H2

Take the value of k i m sorry is -54 and use that to determine the 3 consecutive strange integers.

Finally, verify that when the three consecutive odd integers -109, -107 ,and -105 room added, the sum is -321.