Since there deserve to be <-ℓ, ℓ> orientations and since the orbital kind f has actually ℓ = 3, we should have actually 7 possible orientations v 2 spins, for this reason $7 imes 2 = 14$, for this reason I believed the correct answer was D (14).

You are watching: What is the maximum number of f orbitals that are possible in a given shell?

However, I obtained it wrong and the correct answer is significant as C (2). Is it an error in the test, or am I absent something?


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You"re correct the there space seven possible spatial orientations because that an f-type orbital, and hence seven possible orbitals in one f-type sub-shell. However, the question specifically asks for the maximum number of electrons in one together orbital, and also any solitary atomic orbital, nevertheless of the sub-shell type specified by $l$, have the right to only hold two electrons. This is through virtue the the Pauli exclusion principle. Fourteen would be the maximum number of electrons across an entire f-type sub-shell, yet the question just asks around one orbital.


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The question specifically ask the no.of electron an orbit of f subshell deserve to hold.... Together we understand that f subshell contain 7 orbital and each orbital can hold maximum 2 electons so correct answer would be 2..we can simply know this by acquisition the actual life instance imagine the there is home named f which consists of 7 rooms so likewise in this situation house is a subshell and each room is one orbital... Say thanks to you,


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