n x / 160 = - k x 19.1 rate of reaction is required 222Rn has a half-life the 3.8235 d. 160 Ă— .5^( 19.1/3.8235 ) = 5.0 mg 5.0 mg is the total mass that 222Rn staying in an original 160-milligram sample of 222Rn.

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75 tickets have actually been sold so far.

step-by-step explanation:

in this question it is plainly mentioned the 45 children"s tickets have been sold and this number is 60% that the complete tickets sold.

now let"s i think the total number of tickets offered be x.

then 60% the x = 45

⇒ x(.6) = 45

by separating with .6 top top both the political parties of the equation

⇒ x = 75

therefore 75 tickets have been sold so far.

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